Asked by sudheerkapoor67
5th October 2017,
10:33 PM
Answered by Expert
Answer:
We provide steps to the solution especially for JEE students.
Please follow the below steps:
- Potential difference between AB means the potential difference between the inductor and the capacitor is to be calculated.
i.e (V L + VC)
- Applying kirchoff's voltage law,
- Source voltage = voltage across (resistance + capacitor + inductor)
Vs = V r + V L +Vc
100 cos (100 π t) = IR + (V L + Vc)
(V L + Vc) = 100 cos (100 π t) - IR
Hint:
- The instantaneous voltage across a pure resistor, VR is “in-phase” with current.
- The instantaneous voltage across a pure inductor, VL “leads” the current by 90 degree.
- The instantaneous voltage across a pure resistor, VR is “in-phase” with current.
- The instantaneous voltage across a pure inductor, VL “leads” the current by 90 degree.
- The instantaneous voltage across a pure capacitor, VC “lags” the current by 90 degree.
- Therefore, VL and VC are 180o “out-of-phase” and in opposition to each other.
- Therefore, VL and VC are 180o “out-of-phase” and in opposition to each other.
Answered by Expert
7th October 2017,
9:06 PM
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