Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

Asked by sudheerkapoor67 5th October 2017, 10:33 PM

We provide steps to the solution especially for JEE students.

- Potential difference between AB means the potential difference between the inductor and the capacitor is to be calculated.

i.e (V L + VC

- Applying kirchoff's voltage law,

- Source voltage = voltage across (resistance + capacitor + inductor)

Vs  =  V r + V L  +Vc
100 cos (100 π t) = IR + (V L  + Vc)
(V L  + Vc) = 100 cos (100 π t) - IR

Hint:
- The instantaneous voltage across a pure resistor, VR is “in-phase” with current.
- The instantaneous voltage across a pure inductor, VL “leads” the current by 90 degree.
- The instantaneous voltage across a pure capacitor, VC “lags” the current by 90 degree.
- Therefore, VL and VC are 180o “out-of-phase” and in opposition to each other.

Answered by Expert 7th October 2017, 9:06 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10