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Asked by sudheerkapoor67 5th October 2017, 10:33 PM
Answered by Expert
Answer:

We provide steps to the solution especially for JEE students.

Please follow the below steps:

- Potential difference between AB means the potential difference between the inductor and the capacitor is to be calculated.

i.e (V L + VC

- Applying kirchoff's voltage law,

- Source voltage = voltage across (resistance + capacitor + inductor)

   Vs  =  V r + V L  +Vc
   100 cos (100 π t) = IR + (V L  + Vc) 
(V L  + Vc) = 100 cos (100 π t) - IR

Hint:
- The instantaneous voltage across a pure resistor, VR is “in-phase” with current.
- The instantaneous voltage across a pure inductor, VL “leads” the current by 90 degree.
- The instantaneous voltage across a pure capacitor, VC “lags” the current by 90 degree.
- Therefore, VL and VC are 180o “out-of-phase” and in opposition to each other. 
 

Answered by Expert 7th October 2017, 9:06 PM
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