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ICSE Class 10 Answered

 
Pls advise solution
Asked by vanij1301 | 15 Feb, 2017, 02:28: PM
answered-by-expert Expert Answer
(i) Thermal capacity = 966 J° C-1 = 966 J K-1 
Rise in temperature = 15° C = 15 K
Heat required = Thermal capacity × Rise in temperature
                      = 966 J K-1 × 15 K 
Heat required = 14490 J
 
(ii) Specific heat capacity of iron = Thermal capacity / Mass of iron 
                                                    = 966 J K-1 / 2 kg
 Specific heat capacity of iron = 483 Jkg-1 K-1
Answered by Yashvanti Jain | 15 Feb, 2017, 06:40: PM
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