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Asked by shreehari wadawadagi 20th March 2014, 8:19 PM
Answered by Expert
(i) rightwards double arrow(ii)
Since A subset of B, there is no element in A which does not belong to B.
Thus, A - B = empty set
Hence, (i) rightwards double arrow(ii)
(ii) rightwards double arrow(ii)
A - B = empty setrightwards double arrowA subset ofB rightwards double arrowA U B = B
Hence, (ii) rightwards double arrow(iii)
(iii) rightwards double arrow(iv) rightwards double arrowA U B = B rightwards double arrowA intersectionB = A
Hence, (iii) rightwards double arrow(iv)
(iv) rightwards double arrow(i)
Since, A intersectionB = A rightwards double arrow A subset of B
Thus, (iv) rightwards double arrow(i)
Hence, (i) left right double arrow(ii) left right double arrow(iii) left right double arrow(iv)
Answered by Expert 21st March 2014, 10:51 AM
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