CBSE Class 11-science Answered
?
Asked by smanishkumar2002 | 01 May, 2018, 10:43: AM
Expert Answer
The reaction takes place as
N2 + 3H2 → 2NH3
No. of moles: 1 3 2
1 mole of N2 gives 2 moles of NH3
let's find the mass of N2 for 1 mole
= mole X molar mass
= 1 X 28 =28
the mass of N2 = 28 g
Similarly, for 2 moles of NH3 = mass / given mass at equilibrium.
Given Mass of NH3 is 17 gms
therefore, mass of NH3 = 2 X 17 = 34 gms
1g of NH3 is given by 28/34 g of N2
Therefore 17 g of NH3 is given by (28/34) X 17 g of N2 = 14 gms
Now find the mass of H2 at equilibrium,
Molar mass of H2 = 3 X 2 = 6 ....... ( 3 moles)
mass of NH3 = 34 gm as calculated above,
3 moles of H2 gives 2 moles of NH3
As given 6 g of H2 will give 34 gm of NH3
Therefore for 17 gm of NH3 is given by (6/34)x 17 = 3gm
Therefore the correct option is D
Answered by Ramandeep | 02 May, 2018, 12:03: PM
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