ICSE Class 10 Answered

Asked by Topperlearning User | 14 Sep, 2017, 10:15: AM

Expert Answer

$begin mathsize 12px style fraction numerator straight a squared space plus space straight b squared over denominator ab end fraction space equals space 25 over 12 fraction numerator begin display style straight a squared space plus space straight b squared end style over denominator begin display style 2 ab end style end fraction space equals space fraction numerator begin display style 25 end style over denominator begin display style 24 end style end fraction fraction numerator begin display style open parentheses straight a space plus space straight b close parentheses squared end style over denominator open parentheses straight a space minus space straight b close parentheses squared end fraction space equals space 49 over 1 space space space space space left parenthesis by space componendo space and space dividendo right parenthesis fraction numerator straight a space plus space straight b over denominator straight a space minus space straight b end fraction equals 7 over 1 fraction numerator 2 straight a over denominator 2 straight b end fraction space equals space 8 over 6 fraction numerator begin display style straight a end style over denominator begin display style straight b end style end fraction equals 4 over 3 Let space straight a space equals space 4 straight k space and space straight b space equals space 3 straight k Then comma space fraction numerator straight a cubed space plus space straight b cubed over denominator straight a cubed space minus space straight b cubed end fraction equals fraction numerator begin display style open parentheses 4 straight k close parentheses cubed end style begin display style space end style begin display style plus end style begin display style space end style begin display style begin display style open parentheses 3 straight k close parentheses end style cubed end style over denominator open parentheses 4 straight k close parentheses cubed space minus space open parentheses 3 straight k close parentheses cubed end fraction space equals space 91 over 37 end style$