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E L E C T R O S T A T I C S
E l e c t r i c space f i e l d space d u e space t o space a space c l o s e d space c o n d u c t i n g space s p h e r t e space o f space r a d i u s space R space a t space i t s space s u r f a c e space i s space fraction numerator Q over denominator 4 pi epsilon ring operator R squared end fraction.
w h e r e space t h e space c h a r g e space e n c l o s e d space i s space space Q
i f space w e space w e r e space t o space c a l c u l a t e space t h e space e l e c t r i c space f i e l d space a t space a space d i s tan c e space o u t s i d e space t h e space s p h e r e space comma s h o u l d space w e space u s e space t h e space e n t i r e space d i s tan c e semicolon i. e left parenthesis R plus a right parenthesis
o r space s h o u l d space i space n e g l e c t space t h e space r a d i u s space o f space t h e space s p h e r e
H e r e space a equals d i s tan c e space o f space t h e space p o i n t space c o n s i d e r e d space f r o m space t h e space s u r f a c e space o f space t h e space s p h e r e
t h a n k space y o u.

Asked by preethambasilmartis 13th June 2016, 11:47 AM
Answered by Expert
Answer:

Hi Preetham,

While considering electric field, the charge enclosed inside the sphere (or any conductor) will be as if the entire charge is concentrated at the centre.

Hence, the distance should be taken as R + a = r

So, the field will be

begin mathsize 12px style straight E equals fraction numerator straight Q over denominator 4 πε subscript 0 straight r squared end fraction equals fraction numerator straight Q over denominator 4 πε subscript 0 open parentheses straight R plus straight a close parentheses squared end fraction end style

Answered by Expert 20th June 2016, 6:14 PM
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