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CBSE Class 12-science Answered

E L E C T R O S T A T I C S E l e c t r i c space f i e l d space d u e space t o space a space c l o s e d space c o n d u c t i n g space s p h e r t e space o f space r a d i u s space R space a t space i t s space s u r f a c e space i s space fraction numerator Q over denominator 4 pi epsilon ring operator R squared end fraction. w h e r e space t h e space c h a r g e space e n c l o s e d space i s space space Q i f space w e space w e r e space t o space c a l c u l a t e space t h e space e l e c t r i c space f i e l d space a t space a space d i s tan c e space o u t s i d e space t h e space s p h e r e space comma s h o u l d space w e space u s e space t h e space e n t i r e space d i s tan c e semicolon i. e left parenthesis R plus a right parenthesis o r space s h o u l d space i space n e g l e c t space t h e space r a d i u s space o f space t h e space s p h e r e H e r e space a equals d i s tan c e space o f space t h e space p o i n t space c o n s i d e r e d space f r o m space t h e space s u r f a c e space o f space t h e space s p h e r e t h a n k space y o u.
Asked by preethambasilmartis | 13 Jun, 2016, 11:47: AM
answered-by-expert Expert Answer

Hi Preetham,

While considering electric field, the charge enclosed inside the sphere (or any conductor) will be as if the entire charge is concentrated at the centre.

Hence, the distance should be taken as R + a = r

So, the field will be

begin mathsize 12px style straight E equals fraction numerator straight Q over denominator 4 πε subscript 0 straight r squared end fraction equals fraction numerator straight Q over denominator 4 πε subscript 0 open parentheses straight R plus straight a close parentheses squared end fraction end style

Answered by | 20 Jun, 2016, 06:14: PM

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