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integral space x 2 d x backslash x 4 minus x 2 minus 12
 

Asked by SANAL KUMAR 25th February 2016, 6:51 PM
Answered by Expert
Answer:

begin mathsize 12px style integral fraction numerator straight x squared over denominator straight x to the power of 4 minus straight x squared minus 12 end fraction dx equals integral fraction numerator straight x squared over denominator open parentheses straight x squared minus begin display style 1 half end style close parentheses squared minus open parentheses begin display style 7 over 2 end style close parentheses squared end fraction dx equals integral fraction numerator straight x squared over denominator open parentheses straight x squared plus 3 close parentheses open parentheses straight x squared minus 4 close parentheses end fraction dx equals integral fraction numerator straight x squared over denominator open parentheses straight x squared plus 3 close parentheses open parentheses straight x plus 2 close parentheses open parentheses straight x minus 2 close parentheses end fraction dx equals integral fraction numerator 3 over denominator 7 open parentheses straight x squared plus 3 close parentheses end fraction minus fraction numerator 1 over denominator 7 open parentheses straight x plus 2 close parentheses end fraction plus fraction numerator 1 over denominator 7 open parentheses straight x minus 2 close parentheses end fraction dx equals 3 over 7 cross times fraction numerator 1 over denominator square root of 3 end fraction tan to the power of negative 1 end exponent open parentheses fraction numerator straight x over denominator square root of 3 end fraction close parentheses minus 1 over 7 ln open parentheses straight x plus 2 close parentheses plus 1 over 7 ln open parentheses straight x minus 2 close parentheses plus straight C end style

Answered by Expert 25th February 2016, 7:25 PM
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