## Full fledge assessment videos for constructions

Full fledge assessment (Please watch the above videos before attempting this assessment)

Question 1 of 20
Q1. When parallel lines meet a transversal, they make equal
• alternate angles
• interior angles
• exterior angles
• None of these

### Solution :

When parallel lines meet a transversal, they make equal alternate angles.
Still have doubt? Watch Video
Q2. How many tangents can be drawn to a circle having a diameter 15 cm from a point at a distance of 7.5 cm from the centre?
• 0
• 1
• 2
• 3

### Solution :

The distance from the centre is 7.5 cm. The radius is 7.5 cm. Since the point lies on the circle, 1 tangent can be drawn to the circle.
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Q3. A tangent and radius of the circle make an angle of measure
• 45°
• 90°
• 180°
• 270°

### Solution :

A tangent and radius of the circle make an angle of measure 90°.
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Q4. In the figure below, if AO = 29 cm, XO = 21 cm, then AY =? • 25 cm
• 24 cm
• 22 cm
• 20 cm

### Solution :

Since the tangent is perpendicular to the radius, By Pythagoras' theorem, 292 = 212 + AX2 AX2 = 400 AY = AX = 20 cm
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Q5. If the length of the tangent from the external point P is 12 cm, and the distance of P from the centre is 13 cm, then the radius of the circle is
• 5 cm
• 6 cm
• 7 cm
• 8 cm

### Solution :

By Pythagoras' theorem,  132 = 122 + radius2 radius2 = 25 radius = 5 cm
Still have doubt? Watch Video
Q6. If AB is divided into 3 equal parts at P and R, then PB =?
• 1/4 AR
• 1/2 BA
• 1/4 AB
• 2/3 AB

### Solution :

A-P-R-B If PB = 2x, then BA = 3x.
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Q7. To divide a line segment in 5:3, we have to make
• 5 equal divisions
• 3 equal divisions
• 2 equal divisions
• 8 equal divisions

### Solution :

To divide a line segment in m:n, we have to make m+n equal divisions.
Still have doubt? Watch Video
Q8. To divide a line segment in m:n, we have to make
• M equal divisions
• N equal divisions
• m+n equal divisions
• m-n equal divisions

### Solution :

To divide a line segment in m:n, we have m+n equal divisions.
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Q9. While constructing ∆PQR similar to ∆ABC such that AB:PQ = 3:5, the larger triangle is
• ∆ABC
• ∆PQR
• Both are equal
• None of these
Construction of Similar Triangles

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### Solution :

While constructing ∆PQR similar to ∆ABC such that AB:PQ = 3:5, the larger triangle is DPQR. Still have doubt? Watch Video
Q10. A tangent cuts the circle at
• one point
• two points
• no point
• three points

### Solution :

A tangent cuts the circle at one point.
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Q11. In the figure below, AO = 5 cm and XO = 3 cm, then AX =? • 4 cm
• 5 cm
• 6 cm
• 7 cm

### Solution :

As the radius is perpendicular to the tangent,  By Pythagoras' theorem, 52 = 32 + AX2AX2 = 16 AX = 4
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Q12. Two tangents drawn from the external points to a circle are
• Perpendicular
• Parallel
• Equal
• None of these

### Solution :

Two tangents drawn from the external points to a circle are equal.
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Q13. The angle drawn in a semicircle from the end points of the diameter is
• 30°
• 45°
• 60°
• 90°

### Solution :

The angle drawn in a semicircle from the end points of the diameter is 90°.
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Q14. The centre of a circle lies on the
• Perpendicular
• perpendicular bisector
• perpendicular of its chord
• perpendicular bisector of its chord

### Solution :

The centre of a circle lies on the perpendicular bisector of its chord.
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Q15. The length of the tangent from the external point P is 15 cm, and the distance of P from the centre is 17 cm. So, the radius of the circle is
• 6 cm
• 7 cm
• 8 cm
• 9 cm

### Solution :

By Pythagoras' theorem, 172 = 152 + radius2 radius2 = 64 radius = 8 cm
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Q16. While constructing ∆PQR similar to ∆ABC such that AB:PQ = 3:5, we need to make an acute angle at A and divide it
• 3 times
• 5 times
• 8 times
• 10 times
Construction of Similar Triangles

" >

### Solution :

While constructing a triangle similar to the given triangle, such that their sides are in the ratio m:n, we need to make an acute angle and divide it max (m,n) times.
Still have doubt? Watch Video
Q17. To construct a line parallel to the given line, we use
• The alternate angles property
• The corresponding angles property
• Both A and B
• None of these

### Solution :

To construct a line parallel to the given line, we use the corresponding angles and alternate angles property.
Still have doubt? Watch Video
Q18. In the figure below, ∠XAO = 30°. What is the measure of ∠XOA? • 30°
• 45°
• 60°
• 90°

### Solution :

∠XAO = 30° ∠OXA = 90° So, ∠XOA = 60° … (sum of the angles of a triangle)
Still have doubt? Watch Video
Q19. The length of the tangent from the external point P is 40 cm and the distance of P from the centre is 41 cm, so the radius of the circle is
• 5 cm
• 7 cm
• 8 cm
• 9 cm

### Solution :

By Pythagoras' theorem, 412 = 402 + radius2 radius2 = 81 radius = 9 cm
Still have doubt? Watch Video
Q20. To divide a line segment in 4 equal parts, we need to draw
• perpendicular bisector two times
• perpendicular bisector three times
• perpendicular bisector four times
• none of these

### Solution :

To divide a line segment in 4 equal parts, we need to draw a perpendicular bisector three times.
Still have doubt? Watch Video

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