Asked by  | 15th Mar, 2010, 02:02: AM

Expert Answer:

Answer is d-None of these

ZnS+ 2HClZnCl2+H2S

ZnCl2 +2NaOHZn(OH)2 +2NaCl

If excess sodium hydroxide is added, the precipitate of zinc hydroxide will dissolve, forming a colorless solution of zincate ion

: Zn(OH)2 + 2NaOH → Na2[Zn(OH)4]

Answered by  | 15th Mar, 2010, 10:04: AM

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