Zns
Asked by | 15th Mar, 2010, 02:02: AM
Expert Answer:
Answer is d-None of these
ZnS+ 2HCl
ZnCl2+H2S
ZnCl2 +2NaOHZn(OH)2 +2NaCl
If excess sodium hydroxide is added, the precipitate of zinc hydroxide will dissolve, forming a colorless solution of zincate ion
: Zn(OH)2 + 2NaOH → Na2[Zn(OH)4]
Answered by | 15th Mar, 2010, 10:04: AM
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