Zn+4HNO3 gives Zn[NO3]2+2H2O+2NO2                                                                                               ANSWER THE FOLLOWING QUESTION :                                                                                             1 The volume of NO2 formed at 19.5 g of Zn                                                                                           2 The no of moles of HNO3 taking part in the reaction                                                                             3 The no of molecules of H2O formed                                                                                                     4 what mass of HNO3 is required to produce 145.6L of NO2 at S.T.P

Asked by nibeditamohapatro.publicschool | 15th Aug, 2018, 12:16: AM

Expert Answer:

Given space reaction space is comma

Zn space plus space 4 HNO subscript 3 space rightwards arrow space Zn space open square brackets NO subscript 3 close square brackets subscript 2 space plus space 2 straight H subscript 2 straight O space plus space 2 NO subscript 2

1 space mole space Zn space gives space 2 space mole space of space NO subscript 2

65 space straight g space equals space 1 space mole space of space Zn

19.5 space straight g space equals fraction numerator 19.5 over denominator 65 end fraction

space space space space space space space space space space space space equals 0.3 space mole space of space Zn

1 space mole space Zn space gives space 2 space mole space of space NO subscript 2

0.3 space mole space of space Zn space will space give space equals fraction numerator 0.3 cross times 2 over denominator 1 end fraction

0.3 space mole space of space Zn space will space give space equals space 0.6 space mole space of space space NO subscript 2

1 space mole space space equals space 22.4 space lit

0.3 space mole space space equals space space 22.4 cross times 0.3

space space space space space space space space space space space space space space space equals 13.44 space litre space of space NO subscript 2

For space no. space of space water space molecules colon

Molecular space weight space of space straight H subscript 2 straight O space equals space 18

2 straight H subscript 2 straight O space equals space 36

1 mole space of space straight H subscript 2 straight O space equals space 18

36 space straight H subscript 2 straight O space equals space 2 space mole

1 space mole space equals space 6.022 cross times 10 to the power of 23 space molecules

2 space moles space equals 6.022 cross times 10 to the power of 23 cross times 2

space space space space space space space space space space space space space space equals 1.2 space cross times 10 to the power of 24 space molecules space of space straight H subscript 2 straight O

Now space for space mass space of space HNO subscript 3 space end subscript space required colon

Volume space of space NO subscript 2 space equals 145.6 space lit

1 mole space equals space 22.4 space litre

145.6 space lit space equals fraction numerator 145.6 over denominator 22.4 end fraction

space space space space space space space space space space space space space space space equals 6.5 mole space of space NO subscript 2

From space reaction comma

4 space mol space of space HNO subscript 3 space gives space 2 space mole space of space NO subscript 2

apostrophe straight x apostrophe space mol space of space HNO subscript 3 space will space give space 6.5 space mole space of space NO subscript 2

straight x space equals fraction numerator 6.5 cross times 4 over denominator 2 end fraction

space space space equals space 13 space mole space of space HNO subscript 3

1 space mole space of space HNO subscript 3 space equals 63 straight g divided by mol

13 space mole space of space HNO subscript 3 space equals 13 cross times 63

space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 819 space straight g space of space HNO subscript 3

Answered by Varsha | 16th Aug, 2018, 02:52: PM