Zinc and hydrochloric acid react according to reaction if 0.30 mole zinc are added to hydrochloric acid ,containing0.52 mole HCl, how many moles of H2 are produced. reaction is. Zn( s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)

Asked by FIZA SINGH | 14th May, 2013, 10:25: AM

Expert Answer:

Zn( s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)
 
In this reaction find out the limiting reagent as follows:
0.3 mol Zn x 1mol H2/1 mole Zn = 0.3 mole H2
 
0.52 mole H2 x 1 mole H2/2 mole HCl = 0.26 mole H2
 
This shows that HCl is the limiting reagent in the reaction and Zn is excess reagent.
Since, HCl is the limiting reagent, amount of hydrogen produced will be = 0.26 moles.

Answered by  | 14th May, 2013, 10:40: AM

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