zeros of the polynomial

Asked by yashpinto | 26th Apr, 2010, 11:28: AM

Expert Answer:

Dear Student,

the solution of your question is as follows:

 

Let the two zeros of the given polynomials be α and β.

Now for a quadratic polynomial in standard form i.e. (ax2 + bx + c), we have the following two relations -

α+β = -b/a       ------- (1)

and

αβ = c/a           -------- (2)

 

Comparing the given problem with standard form, we get

a= (k2+4)

b= 13

c= 4k

 

Also, for the given problem, one zero is reciprocal of the other,

=> β = 1/α

So, from equation (2) we have,

 

Regards Topperlearning.

Answered by  | 26th Apr, 2010, 01:29: PM

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