zeros of the polynomial
Asked by yashpinto | 26th Apr, 2010, 11:28: AM
Dear Student,
the solution of your question is as follows:
Let the two zeros of the given polynomials be α and β.
Now for a quadratic polynomial in standard form i.e. (ax2 + bx + c), we have the following two relations -
α+β = -b/a ------- (1)
and
αβ = c/a -------- (2)
Comparing the given problem with standard form, we get
a= (k2+4)
b= 13
c= 4k
Also, for the given problem, one zero is reciprocal of the other,
=> β = 1/α
So, from equation (2) we have,
Regards Topperlearning.
Answered by | 26th Apr, 2010, 01:29: PM
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