Z1=(√3-1)+(√3+1)i Z2 =-√3+1 arg(Z1Z2)=?

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Z1=(√3-1)+(√3+1)i Z2 =-√3+1 arg(Z1Z2)=?

Asked by manishachand010 | 15 Apr, 2022, 12:28: PM

Expert Answer

z₁ = (√3-1) + (√3+1)i

z₂ = -√3 + 1

z subscript 1 z subscript 2 equals open square brackets open parentheses square root of 3 minus 1 close parentheses space plus space open parentheses square root of 3 plus 1 close parentheses i close square brackets open square brackets negative square root of 3 space plus space 1 close square brackets equals open parentheses square root of 3 minus 1 close parentheses open parentheses negative square root of 3 plus 1 close parentheses plus open parentheses square root of 3 plus 1 close parentheses open parentheses negative square root of 3 plus 1 close parentheses i equals negative 3 plus square root of 3 plus square root of 3 minus 1 plus open parentheses negative 3 minus square root of 3 plus square root of 3 plus 1 close parentheses i equals negative 4 plus 2 square root of 3 plus i open parentheses negative 2 close parentheses a r g left parenthesis z subscript 1 z subscript 2 right parenthesis equals tan to the power of negative 1 end exponent open parentheses fraction numerator negative 2 over denominator negative 4 plus 2 square root of 2 end fraction close parentheses equals tan to the power of negative 1 end exponent open parentheses negative fraction numerator 1 over denominator square root of 2 minus 2 end fraction close parentheses

Answered by Renu Varma | 18 Apr, 2022, 11:22: AM

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