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Asked by manveerajput | 29th Aug, 2020, 02:14: PM

Expert Answer:

To Calculate molar conductivity at infinity dilution of NH4OH, We'll use kohlrausch's law-
logical and subscript NH subscript 4 OH end subscript superscript straight o space equals logical and subscript NH subscript 4 Cl end subscript superscript straight o space plus logical and subscript NH subscript 4 OH end subscript superscript straight o space minus logical and subscript NaCl superscript straight o
logical and subscript NH subscript 4 OH end subscript superscript straight o equals space 129.8 plus 218.4 minus 108.9
logical and subscript NH subscript 4 OH end subscript superscript straight o equals space 239.9 space Scm squared mol to the power of negative 1 end exponent

Molar space conductivity

logical and subscript NH subscript 4 OH end subscript superscript straight m space equals space 9.33 space straight S space Cm squared mol to the power of negative 1 end exponent

straight alpha equals fraction numerator logical and subscript NH subscript 4 OH end subscript superscript straight m over denominator logical and subscript NH subscript 4 OH end subscript superscript straight o end fraction equals fraction numerator 9.33 over denominator 239.9 end fraction equals 0.03915

in space percent sign comma space straight alpha equals 3.915 space percent sign space

Answered by Ravi | 2nd Sep, 2020, 04:28: PM