y=sin^-1[sq root of (1+x)+sq root of (1-x)/2]

Asked by RajeshMudgal | 15th Mar, 2013, 12:11: PM

Expert Answer:

If the question is to differentiate y with respect to x, then the answer is as follows:
 

Answered by  | 16th Mar, 2013, 09:31: PM

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