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y=log(logx) then dy/dx=?
Asked by mudapaka.vinay | 06 Jan, 2020, 02:39: PM
answered-by-expert Expert Answer
y = log(logx)
dy/dx = 1/log x × 1/x
dy/dx = 1/xlog x
Answered by Sneha shidid | 07 Jan, 2020, 09:55: AM
JEE main - Maths
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Asked by mnsdewari | 03 Apr, 2020, 06:52: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by mudapaka.vinay | 06 Jan, 2020, 02:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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