• y=log(logx) then dy/dx=?

Asked by mudapaka.vinay | 6th Jan, 2020, 02:39: PM

Expert Answer:

y = log(logx)
dy/dx = 1/log x × 1/x
dy/dx = 1/xlog x

Answered by Sneha shidid | 7th Jan, 2020, 09:55: AM

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