x/y+y/x=1 then find x^3-y^3

Asked by sanjaygujar2015 | 13th Jan, 2018, 07:27: PM

Expert Answer:

in this question it will be either -1 or x3+y3.

answer = x/y+y/x=-1

x/y=-1-y/x

x/y=-x-y/x

x2=-xy-y2

x2+xy+y2=0

now, x3-y3=(x-y)(x2+xy+y2)

(x-y)*0=0

 

Answered by Arun | 15th Jan, 2018, 12:47: PM

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