X and Y can paint the house in 18 days, Y and Z in 24 days and X and Z in 36 days. In how many days Y will finish it separately?
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
X and Y can paint the house in 18 days (X + Y)'s 1 day's work =
Y and Z can paint the house in 24 days (Y + Z)'s 1 day's work =
X and Z can paint the house in 36 days (X + Z)'s 1 day's work =
Adding, we get
2(X + Y + Z)'s 1 day's work =
Thus, (X + Y + Z)'s 1 day's work =
Y's 1 day's work = [(X + Y + Z)'s 1 day's work] - [(X + Z)'s 1 day's work]
Hence, Y alone can paint the house in days.
Answered by | 4th Jun, 2014, 03:23: PM
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