x^3-3x^2+3x+7

Asked by Sukhad Sahu | 12th May, 2013, 02:48: PM

Expert Answer:

f(x)  = x^3-3x^2+3x+7 
Using remainder theorem f(-1) = 0
Hence, x+1 is a factor of f(x)
Hence, then using the long division method with x+1 as the divisor
f(x) = (x+1) (x^2-4x+7)

Answered by  | 12th May, 2013, 04:25: PM

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