x\3+3\6-x=2(6-x)\15

Asked by sheetaltakiar | 21st May, 2020, 04:19: PM

Expert Answer:

To solve: x/3 + 3/(6-x) = 2(6-x)/15
x over 3 plus fraction numerator 3 over denominator 6 minus x end fraction equals fraction numerator 2 open parentheses 6 minus x close parentheses over denominator 15 end fraction
rightwards double arrow fraction numerator x open parentheses 6 minus x close parentheses plus 9 over denominator 3 open parentheses 6 minus x close parentheses end fraction equals fraction numerator 2 open parentheses 6 minus x close parentheses over denominator 15 end fraction
rightwards double arrow 6 x minus x squared plus 9 equals fraction numerator 2 open parentheses 6 minus x close parentheses squared over denominator 5 end fraction
rightwards double arrow 30 x minus 5 x squared plus 45 equals 2 x squared plus 72 minus 24 x
rightwards double arrow 7 x squared minus 54 x plus 27 equals 0
S o l v e space t h i s space q u a d r a t i c space e q u a t i o n space a n d space g e t space t h e space v a l u e s space o f space x

Answered by Renu Varma | 22nd May, 2020, 10:23: AM