write the value of the 4 quantum numbers of 11th electron of sulphur?

Asked by Aishwarya Devadasan | 29th Nov, 2013, 01:30: PM

Expert Answer:


 The 11th electron of sulphur is in third shell that is in 3s orbital. Hence,
Principal quantum number, n = 3
Azimuthal quntum number, l should be 0 to n-1 that means l = 0, 1, 2.
                                                                                                                 s, p, d.
As l is 0 for s.
Hense l= 0 for 11th electron.
Magnetic quantum number, ml= -l,0,+l. Here ml= 0 as l = 0.
Spin quantum number for 11th electron will be +1/2 as an electron with an up arrow means it has an electron spin of +1/2.
n=3, l=0, ml=0, and ms = +1/2 for the 11 th electron.

Answered by Prachi Sawant | 4th Dec, 2013, 12:21: PM

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