write the value of tan-1[2 sin {2 cos-1(root 3/ 2)}]

Asked by  | 27th May, 2013, 01:17: PM

Expert Answer:

Answer  = tan-1[2 sin {2 cos-1(31/2/ 2)}] 
= tan-1[2 sin {2 (pi/6)}]  
     {as we know cos pi/6 =   3 1/2/2  so cos -1 (1/2/2 ) = pi/6  }
=  tan-1[2 sin (pi/3)]
= tan-1 [ 2 (1/2/2 ) ]                       {sin pi / 3 = 1/2/2 }
tan-1 [ 1/2]
= pi/3  Answer                                        

Answered by  | 27th May, 2013, 04:07: PM

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