CBSE Class 12-science Answered
write the value of tan-1[2 sin {2 cos-1(root 3/ 2)}]
Asked by | 27 May, 2013, 01:17: PM
Expert Answer
Answer = tan-1[2 sin {2 cos-1(31/2/ 2)}]
= tan-1[2 sin {2 (pi/6)}]
{as we know cos pi/6 = 3 1/2/2 so cos -1 (3 1/2/2 ) = pi/6 }
= tan-1[2 sin (pi/3)]
= tan-1 [ 2 (3 1/2/2 ) ] {sin pi / 3 = 3 1/2/2 }
= tan-1 [ 3 1/2]
= pi/3 Answer
Answered by | 27 May, 2013, 04:07: PM
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