Will a larger capacitance C allow more charge to be put onto the plates for a given value of the potential difference V?Explain

Asked by Biju Jacob | 10th May, 2013, 10:58: PM

Expert Answer:

Yes, that is true. This can be explained by considering -
C = q/V
 
So, C is directly proportional to q (charge on the plates) if V is constant. So, for larger value of C, larger charge will be put on capacitor (can be parallel plates or anything else). 

Answered by  | 11th May, 2013, 02:49: AM

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