Why joule thomson coefficient for ideal gas is zero?

Asked by ashutosharnold1998 | 8th Aug, 2019, 12:11: AM

Expert Answer:

An ideal gas undergoes neither cooling nor heating on adiabatic expansion in Joule-Thomson experiment hence Joule-Thomson co-efficient for an ideal gas is zero.
 
Explanation:

The intermolecular forces of attraction like Van der Waals forces in an ideal gas are negligible. Hence no energy is used up in overcoming these forces of attraction when the gas expands adiabatically. Thus the internal energy of the gas does not fall and therefore the temperature does not fall.

Answered by Ramandeep | 8th Aug, 2019, 12:18: PM

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