CBSE Class 10 Answered
Why is the height of the object always considered above the principle axis?
Asked by | 23 Dec, 2012, 02:34: PM
Expert Answer
Here the object height will be taken as=-h1
image height =+h2
Object distance=-u, image distance=+v
so magnification=m=-v/u=-h2/h1
positive or negative sign one has to take according to the question.
Answered by | 24 Dec, 2012, 03:29: PM
Application Videos
Concept Videos
CBSE 10 - Physics
Asked by agankitgupta938 | 18 Apr, 2024, 04:29: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by infinityupgraded | 13 Apr, 2024, 08:17: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by suryamr2019 | 08 Mar, 2024, 04:32: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by saurabhjd527 | 30 Jan, 2024, 07:55: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by subrasixty | 13 Jan, 2024, 05:05: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nandanagnair | 17 Dec, 2023, 03:44: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by namish1088 | 16 Nov, 2023, 08:09: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by 0 0 | 19 Oct, 2023, 03:51: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by bubbynaik77 | 29 Sep, 2023, 09:34: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by gurcharansingh37306 | 10 Sep, 2023, 12:53: PM
ANSWERED BY EXPERT