Why is the height of the object always considered above the principle axis?

Asked by  | 23rd Dec, 2012, 02:34: PM

Expert Answer:

Here the object height will be taken as=-h1
image height =+h2
Object distance=-u, image distance=+v
so magnification=m=-v/u=-h2/h1
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Answered by  | 24th Dec, 2012, 03:29: PM

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