Why is the height of the object always considered above the principle axis?
Asked by
| 23rd Dec, 2012,
02:34: PM
Expert Answer:
Here the object height will be taken as=-h1
image height =+h2
Object distance=-u, image distance=+v
so magnification=m=-v/u=-h2/h1
positive or negative sign one has to take according to the question.
Answered by
| 24th Dec, 2012,
03:29: PM
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