why in series combination the potential difference is unequal and in parallel combination it is equal?why is this sooo.?

Asked by lakshay | 25th Apr, 2012, 08:31: PM

Expert Answer:

Series Resistor Voltage

The voltage across each resistor connected in series follows different rules to that of the series current. We know from the above circuit that the total supply voltage across the resistors is equal to the sum of the potential differences across R1 , R2 and R3 ,  VAB = VR1 + VR2 + VR3 = 9V.

Using Ohm's Law, the voltage across the individual resistors can be calculated as:

Voltage across R1 = IR1 =  1mA x 1k? = 1V

Voltage across R2 = IR2 =  1mA x 2k? = 2V

Voltage across R3 = IR3 =  1mA x 6k? = 6V

giving a total voltage VAB of ( 1V + 2V + 6V ) = 9V which is equal to the value of the supply voltage. Then the sum of the potential differences across the resistors is equal to the total potential difference across the combination and in our example this is 9V.

The equation given for calculating the total voltage in a series circuit which is the sum of all the individual voltages added together is given as:

Then series resistor networks can also be thought of as "voltage dividers" and a series resistor circuit having N resistive components will have N-different voltages across it while maintaining a common current.

By using Ohm's Law, either the voltage, current or resistance of any series connected circuit can easily be found and resistor of a series circuit can be interchanged without affecting the total resistance, current, or power to each resistor.

Answered by  | 26th Apr, 2012, 10:12: AM

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