Why I avg. (Current average) multiplied by Vavg (voltage average) and Time period does not give me heat loss in full cycle ?
As I know I avg gives me dc component for ac ,I can take + I avg & -I avg for for +half cycle and -half cycle respectively,then net current will be zero in full cycle but both the current are responsible for heat production in ac so why can'take and do
I avg ×v avg×T= Heat produced in ac current .
(I know that vrms ×Irms×T will give me heat loss )
But my quetion it is why it is wrong which I had first .
Asked by Jaydeepkalal2003 | 16th Aug, 2021, 09:32: PM
Alternating voltage is assumed to be sinusoidal waveform of period T .
Since waveform repeats after every time period T , we need to average the voltage variation for a time period T
Let V = Vm sin(ωt)
If we average over a time period T , then we have
Hence average square of instantaneous voltage is detrmined and square-root of this average is considered
as RMS ( Root-mean-square ) value of voltage
Similarly RMS current over time period T of full cycle is determined .
Product of RMS voltage and RMS current gives average power
If average power is multiplied by time t , we get heat energy generated for time t .
Basically, answer to your question is averaging has to be done for full cycle , not for half cycle,
because waveform repeats after every full cycle.
Answered by Thiyagarajan K | 16th Aug, 2021, 10:18: PM
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