Why are Zn and PB compounds not distinguishable upon addition of NaOH solution? (1 mark).
Asked by bjayanta | 14th Nov, 2016, 09:46: PM
Certain metals like Zinc, Aluminium and Lead react with only hot caustic NaOH/KOH solution to give the corresponding soluble salt with the liberation of hydrogen gas.
Metal + Alkali → Salt + Hydrogen
1.Zinc
Zn + 2NaOH → Na2ZnO2 + H2
Sodium zincate
(Colourless)
2.Aluminium
Al + 2NaOH + 2H2O → 2NaAlO2 + H2
Sodium meta aluminate
(Colourless)
3. Lead
Pb + 2NaOH → Na2PbO2 + H2
Sodium plumbate
(Colourless)
So upon additon of excess NaOH/KOH these compounds are not distinguishable.
Metal + Alkali → Salt + Hydrogen |
1.Zinc Zn + 2NaOH → Na2ZnO2 + H2 Sodium zincate (Colourless) |
2.Aluminium Al + 2NaOH + 2H2O → 2NaAlO2 + H2 Sodium meta aluminate (Colourless)
|
3. Lead Pb + 2NaOH → Na2PbO2 + H2 Sodium plumbate (Colourless) |
Answered by Vaibhav Chavan | 15th Nov, 2016, 06:02: PM
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