CBSE Class 10 Answered
who to solve 2x+3y+5=0
3x+2y+7=0
Asked by ashwinialgure09 | 17 Jul, 2020, 07:26: AM
2x+3y+5=0 ... (i)
3x+2y+7=0 ... (ii)
Let's solve using elimination method
Multiplying (i) by 2 and (ii) by 3, we get
4x+6y+10=0 ... (iii)
9x+6y+21=0 ... (iv)
Subtracting (iii) from (iv), we have
x = -11/5
Substituting in (i), we get x = -1/5
Answered by Renu Varma | 17 Jul, 2020, 12:31: PM
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