Which term of the A.P. 3,15,27,39,...is 132 more than the 54th term ?
Asked by Amuthavalli Thayyal Gopala Krishnan | 23rd Nov, 2013, 08:39: PM
Expert Answer:
a = 3
d = 15 - 3 = 12
Let the required term be the nth term.
an = a + (n-1)d
a54 + 132 = 32 + 53 * 12 + 132
= 32 + 636 + 132 = 800
an = 800
800 = 32 + (n-1) 12
768 = (n-1)12
n-1 =768 / 12 = 64
n = 64 + 1 = 65
Thus, 65th term is 132 more than 54th term
a = 3
d = 15 - 3 = 12
Let the required term be the nth term.
an = a + (n-1)d
a54 + 132 = 32 + 53 * 12 + 132
= 32 + 636 + 132 = 800
an = 800
800 = 32 + (n-1) 12
768 = (n-1)12
n-1 =768 / 12 = 64
n = 64 + 1 = 65
Thus, 65th term is 132 more than 54th term
Answered by | 23rd Nov, 2013, 11:21: PM
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