where should an object be held from a concave mirror of focal length of 15cm so as to form a real im

Asked by twinkly_sony | 28th Jun, 2009, 07:56: PM

Expert Answer:

given: f = - 15 cm; m = - 2

since m = - v / u

v = 2 u

using (1 / f) = (1 / v) + (1 / u)

(1 / -15) = (1 / 2 u) + (1 / u) = 3 / 2u

u = - 22.5 cm

Answered by  | 7th Jul, 2009, 04:08: PM

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