where should an object be held from a concave mirror of focal length of 15cm so as to form a real im
Asked by twinkly_sony
| 28th Jun, 2009,
07:56: PM
Expert Answer:
given: f = - 15 cm; m = - 2
since m = - v / u
v = 2 u
using (1 / f) = (1 / v) + (1 / u)
(1 / -15) = (1 / 2 u) + (1 / u) = 3 / 2u
u = - 22.5 cm
Answered by
| 7th Jul, 2009,
04:08: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change