When x molecules are removed from 200mg of N2O, 2.89×10^-3 moles of N20 are left.x will be? (pls explain in detail)

Asked by pb_ckt | 22nd Apr, 2019, 11:17: PM

Expert Answer:

1 space M o l e space o f space N subscript 2 O space equals space 44 g space equals space 6.023 cross times 10 to the power of 23 space M o l e c u l e s space
S o comma space 0.2 g space equals space fraction numerator 6.023 cross times 10 to the power of 23 cross times 0.2 over denominator 44 end fraction space equals space 2.73 cross times 10 to the power of 21 space M o l e c u l e s.

N o w comma space a c c o r d i n g space t o space q u e s t i o n space

left parenthesis 2.73 cross times 10 to the power of 21 right parenthesis minus x space equals space 2.98 cross times 10 to the power of negative 3 end exponent

o r comma space x space equals left parenthesis 2.73 cross times 10 to the power of 21 right parenthesis minus 2.98 cross times 10 to the power of negative 3 end exponent

S i n c e space t h e space v a l u e space 2.98 cross times 10 to the power of negative 3 end exponent space i s space v e r y space s m a l l space s o comma space m o l e c u l e s space w i l l space b e space o r d e r space o f space 10 to the power of 21.

Answered by Sumit Chakrapani | 23rd Apr, 2019, 12:43: AM

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