when the effect of aerodynamic drag is included,the acceleration of a ball moving upward is given by,a(u)=-g-k(v)^2 and while moving down it is given by a(d)=-g+k(v)^2 .where k is +ve constant v is speed in m/s. if initial velocity is 30m/s when ball is thrown from ground level find maximum height h and speed v(f) upon impact with the ground . take k=0.006 SI and assume g is constant

Asked by advait2163 | 11th Apr, 2011, 11:37: PM

Expert Answer:

We have given that
 
 as the acceleration of ball moving upwards and downwards.
 
In upward direction  
In downward direction
Required velocity will be
v=u+at
 
Required height
 
 

Answered by  | 2nd May, 2011, 09:29: PM

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