WHEN RESISTOR OF RESISTANCE R1 AND R2 ARE CONNECTED IN PARALLEL THE NET RESISTANCE IS 3OHM WHEN CONNECTED IN SERIES ITS VALUE IS 1.6OHM . CALCULATE VALUE OF R1 AND R2.

Asked by PALLAVI GARG | 5th Jun, 2013, 11:27: AM

Expert Answer:

So, For series connection, R1 + R2 = 1.6  i.e. R1 = 1.6 - R2
Also, for parallel connection 1/R1+ 1/R2 = 1/3
1/(1.6-R2)+ 1/R2 = 1/3
3(R2) (1.6-R2) = 1.6
-3R2^2 + 4.8R2 - 1.6 = 0
 
Solving quadratic equation, you will get that R2 = 1.126 ohms or 0.473 ohm
Hence the resistance of 2 resistors is 1.126 ohms or 0.473 ohms. 

Answered by  | 5th Jun, 2013, 07:18: PM

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