When lead sulphide, PbS and lead oxide, PbO, are heated together the products are lead metal and sulphur dioxide, SO2.
PbS(s) + 2PbO(s) 3Pb (l) + SO2 (g).
If 14.0 g of lead oxide reacts according to the above equation, how many (a) moles of lead (b) grams of lead, (c) atoms of lead and (d) grams of sulphur dioxide are formed?
(Atomic mass : Pb = 207.0, S = 32.1 ; O =16.0)
Asked by seeni2005 | 24th Feb, 2021, 12:34: PM
This question is based on stoichiometry.
Firstly let's caclculate the moles of PbO.
Answered by Ravi | 24th Feb, 2021, 05:14: PM
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