CBSE Class 11-science Answered
When 50 ml of HCl reacts With 10gm of CaCO3,Normality of solution is?
Asked by achyutdhukuchhu50 | 01 Jan, 2020, 06:46: AM
Expert Answer
CaCO3 + 2HCl -----------> CaCl2 + H2CO3
Molecular mass of CaCO3 = 100
Moles of CaCO3 =10/100=0.1
1 mole of Calcium Carbonate requires 2 mole.
Normality= Number of gm equivalent of HCl / Volume of solution in Litre
=(0.2/50)*1000
=4 N
Answered by Ravi | 01 Jan, 2020, 03:23: PM
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