When 50 ml of HCl reacts With 10gm of CaCO3,Normality of solution is?

Asked by achyutdhukuchhu50 | 1st Jan, 2020, 06:46: AM

Expert Answer:

CaCO3 + 2HCl -----------> CaCl2 + H2CO3
 
Molecular mass of CaCO3 = 100
 
Moles of CaCO3 =10/100=0.1
 
1 mole of Calcium Carbonate requires 2 mole.
 
Normality= Number of gm equivalent of HCl / Volume of solution in Litre
              =(0.2/50)*1000
              =4 N

Answered by Ravi | 1st Jan, 2020, 03:23: PM