what will be the formulae for maximum charge that can be given to a conductor of radius of curvature r .
Asked by ashik kumar | 16th Dec, 2011, 10:32: AM
Expert Answer:
a capacitor can not hold as much charge as is given to it.
because, after a certain limit ie breakdown voltage it will leak into the environment.
V=Q/C
Q=4??0 r V
here if we put the value of r and max V then can find Q.
Answered by | 19th Dec, 2011, 12:08: PM
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