what will be the formulae for maximum charge that can be given to a conductor of radius of curvature r .

Asked by ashik kumar | 16th Dec, 2011, 10:32: AM

Expert Answer:

a capacitor can not hold as much charge as is given to it.
because, after a certain limit ie breakdown voltage it will leak into the environment.
V=Q/C 
Q=4??0 r V
here if we put the value of r and max  V then can find Q.

Answered by  | 19th Dec, 2011, 12:08: PM

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