CBSE Class 11-science Answered
What volume of oxygen at NTP is required to burn 36 grams of butane
Asked by havramaimoon | 12 Jun, 2024, 22:03: PM
Expert Answer
1 mole (58 g) of butane requires 6.5 moles of oxygen to burn completely.
Therefore, 36 g means 0.62 moles of butane requires 4 moles of oxygen to burn completely.
1 mole of oxygen is 22.4 L at NTP.
So, 4 moles of oxygen is 89.6 L at NTP.
Answered by | 29 Jul, 2024, 10:49: AM
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