What volume of H2 is liberated under similar conditions which released 2.24 dm3 O2 by electrolysis of water

Asked by Anil | 12th May, 2017, 02:37: PM

Expert Answer:

The electrolytic reaction of water is 
2H2O  → 2H2  +  O2
Thus, the volume of hydrogen produced is just the double the volume of oxygen.
So, the volume of H2 is liberated under similar conditions which released 2.24 dm3 O2 by electrolysis of water is 
2×2.24 = 4.48 dm3 hydrogen.

Answered by Prachi Sawant | 12th May, 2017, 03:55: PM