What volume of H2 is evolved at S.T.P when 2.7 g aluminium reacts completely with aqueous NaOH

Asked by Anil | 13th May, 2017, 12:50: PM

Expert Answer:

The chemical reaction is 
2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2
 
Atomic mass of H2 = 27
 
For 2x27 the H2 liberated is 3x22.4 L as at STP 1 mole of H2 is 22.4 L
So, 2.7 g Al liberates 2.7x3x22.4/2x27 = 3.36 L H2

Answered by Prachi Sawant | 13th May, 2017, 08:31: PM