What volume of a solution of Hcl containing 73g/litre would suffice for the exact nuetralisation of NaOH obtained by allowing 0.46g of metallic sodium to react with water?

Asked by goyatvanshika55 | 15th Jun, 2019, 06:36: PM

Expert Answer:

The reactions are 
Na + H2O →  NaOH + 1/2 H2  
NaOH + HCl → NaCl + H2O
Meq of HCl = Meq of NaOH  = Meq of Na
fraction numerator 73 over denominator 36.5 end fraction cross times V equals fraction numerator 0.46 over denominator 23 end fraction 1000

V space cross times 2 equals 0.02 cross times 1000

V equals 20 over 2

V equals 10 space m l
Volume required is 10  ml

Answered by Varsha | 16th Jun, 2019, 08:54: AM

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