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WHAT VOLUME OF 95 % SULPHURIC ACID ( DENSITY = 1.85 g cm^-3 ) AND WHAT MASS OF WATER MUST BE TAKEN TO PREPARE 100 cm^3 OF 15 % SOLUTION OF SULPHURIC ACID ( DENSTIY = 1.10 g cm^-3)?

Asked by kandappan | 02 Apr, 2020, 08:07: PM

### To find:Volume of 95% sulphuric acid (density = 1.85 g/mL)Mass of water to prepare 100 mL of 15% solution of sulphuric acid (density = 1.10 g/mL)Solution: Volume of the solution = 100 cm2 Density of the solution = 1.10 g/cm3 Therefore, Mass of 100 cm3 of solution = 100 x 1.10 g =110 g The given solutions is 15%. Therefore, 100 g of solution contains 15 g of H2SO4 Then, mass H2SO4 in 110 g (100 cm3 ) of solution =  Mass of water in 110 g (100cm3 ) of solution = (110 - 16.5) g = 93.5 g To obtain 100 cm3 of 15 % solution acid, we require the given information. Mass of water = 93.5 g Mass of H2SO4 (100% pure) = 16.5 g Since, the given sulphuric acid is 95% pure, hence, Mass of H2SO4 (95%) will be required =

Answered by Ramandeep | 03 Apr, 2020, 11:03: AM

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