CBSE Class 12-science Answered

To find:

Volume of 95% sulphuric acid (density = 1.85 g/mL)

Mass of water to prepare 100 mL of 15% solution of sulphuric acid (density = 1.10 g/mL)

 

Solution:

Volume of the solution = 100 cm²

Density of the solution = 1.10 g/cm³

Therefore, Mass of 100 cm³ of solution = 100 x 1.10 g =110 g

The given solutions is 15%. Therefore, 100 g of solution contains 15 g of H₂SO₄

Then, mass H₂SO₄ in 110 g (100 cm3 ) of solution = 

Mass of water in 110 g (100cm3 ) of solution = (110 - 16.5) g = 93.5 g

To obtain 100 cm³ of 15 % solution acid, we require the given information.

Mass of water = 93.5 g

Mass of H₂SO₄ (100% pure) = 16.5 g

Since, the given sulphuric acid is 95% pure, hence,

Mass of H₂SO₄ (95%) will be required =