What temperature would be necessary to double the volume of a gas initially at s.t.p. if the pressure is decreased by 50% ?

                                Ans [0℃]

 

Asked by aadrica.kanika | 27th Dec, 2018, 12:27: PM

Expert Answer:

Given:
At STP
 
P1 =760 mmHg
 
V1 = V1
 
T1 = 273 K
 
P2 = 50% OF P1 
 
    = 380 mmHg
 
V2 =2V1
 
T1 = ?
 
 
We have,
 
Gas equation,
 
fraction numerator straight P subscript 1 straight V subscript 1 over denominator straight T subscript 1 end fraction space equals space fraction numerator begin display style straight P subscript 2 straight V subscript 2 end style over denominator begin display style straight T subscript 2 end style end fraction space

fraction numerator 760 cross times straight V subscript 1 over denominator 273 end fraction space equals space fraction numerator 380 cross times 2 straight V subscript 1 over denominator straight T subscript 2 end fraction


straight T subscript 2 space end subscript space equals space fraction numerator 273 cross times 380 cross times 2 up diagonal strike straight V subscript 1 end strike over denominator 760 cross times up diagonal strike straight V subscript 1 end strike end fraction

straight T subscript 2 space equals space 273 space straight K
 
The temperature necessary to double the volume of a gas is 273 K or 0 °C.
 

Answered by Varsha | 28th Dec, 2018, 11:07: AM