What osmotic pressure would 1.25 molal sucrose solution exhibit at 25 degree Celsius the density of solution is 1.34 gram per ml

Asked by Singh.sonali5775 | 13th Jul, 2018, 07:15: PM

Expert Answer:

Formula colon space
Osmotic space pressure space left parenthesis straight n right parenthesis space equals space straight i space straight n space RT over straight V space equals space iMRT
For space Molarity space straight M space equals space fraction numerator left parenthesis 1000 straight m cross times straight d right parenthesis over denominator left parenthesis 1000 plus straight m cross times straight M subscript straight w right parenthesis end fraction
space space space space space space space space space space space space space space space space space space
Lets space first space find space out space the space molarity space of space the space solution comma
Molarity space straight M space equals space space fraction numerator left parenthesis 1000 cross times 1.25 cross times 1.34 right parenthesis over denominator left parenthesis 1000 plus 1.25 cross times 342 right parenthesis end fraction space equals 1.733 straight M

Now comma space straight n space equals space iMRT space space space left parenthesis space for space sucrose space straight i space equals space 1 right parenthesis
space space space space space space space space space space space space space equals space 1 space cross times 1.773 cross times 0.082 cross times 298 space space space
space space space space space space space space space space space space space equals space 28.6 space atm

Answered by Ramandeep | 14th Jul, 2018, 09:51: PM