What mass of slaked lime would be required to decompose completely 4 grams of ammonium chloride and what would be the mass of each products ?

Asked by Manoj | 8th Jul, 2013, 09:00: PM

Expert Answer:

Ca(OH)2            +   2NH4Cl               ?   CaCl2  +           2NH3  +       2H2O
40  + 2(1 + 16)      2( 14+4 +35.5)          (40+2x35.5+) +  2(14 + 3)  + 2(2+16)
74gm                      107gm                     111gm              34gm           36gm
 
1. 107 gms of NH4Cl  is decomposed by 74 gms of Ca(OH)2
 Therefore, 4 gms of NH4Cl would be decomposed by ... 74 x 4/107
                                                                               = 2.766 gms
 
2. 107 gms of NH4Cl produces 111 gms of CaCl2
Therefore, 4 gms of NH4Cl would be produced by ... 111 x 4/107
                                                                           = 4.15 gms
 
3. 107 gms of NH4Cl gives 34 gms of NH3
Therefore, 4 gms of NH4Cl would give ... 34 x 4/ 107
                                                         = 1.271 gms
 
4. 107 gms of NH4Cl gives 36 gms of H2O
Therefore, 4 gms of NH4Cl would give ... 36 x 4/ 107
                                                         = 1.345 gms
 
 
 
 
 

Answered by  | 10th Jul, 2013, 01:21: AM

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