CBSE Class 11-science Answered
What mass of slaked lime would be required to decompose completely 4 grams of ammonium chloride and what would be the mass of each products ?
Asked by Manoj | 08 Jul, 2013, 09:00: PM
Expert Answer
Ca(OH)2 + 2NH4Cl ? CaCl2 + 2NH3 + 2H2O
40 + 2(1 + 16) 2( 14+4 +35.5) (40+2x35.5+) + 2(14 + 3) + 2(2+16)
74gm 107gm 111gm 34gm 36gm
1. 107 gms of NH4Cl is decomposed by 74 gms of Ca(OH)2
Therefore, 4 gms of NH4Cl would be decomposed by ... 74 x 4/107
= 2.766 gms
2. 107 gms of NH4Cl produces 111 gms of CaCl2
Therefore, 4 gms of NH4Cl would be produced by ... 111 x 4/107
= 4.15 gms
3. 107 gms of NH4Cl gives 34 gms of NH3
Therefore, 4 gms of NH4Cl would give ... 34 x 4/ 107
= 1.271 gms
4. 107 gms of NH4Cl gives 36 gms of H2O
Therefore, 4 gms of NH4Cl would give ... 36 x 4/ 107
= 1.345 gms
Answered by | 10 Jul, 2013, 01:21: AM
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