What mass of nitrogen dioxidde can be obtained by heating 11.1 g of lead nitrate

Asked by lovemaan5500 | 26th Nov, 2017, 06:39: AM

Expert Answer:

2 Pb left parenthesis NO subscript 3 right parenthesis subscript 2 rightwards arrow 2 PbO space plus space 4 plus straight O subscript 2

So comma space molecular space weight space of space Pb left parenthesis NO subscript 3 right parenthesis subscript 2 space space space 2 cross times 331 equals space 662 space straight g space
space space space space space space space molecular space weight space of space NO subscript 2 space end subscript space space space space space space space space space 4 cross times 46 space space equals 184 space straight g
space space space space space 662 space straight g space of space space Pb left parenthesis NO subscript 3 right parenthesis subscript 2 space space give space space 184 space straight g space of space space NO subscript 2 space end subscript space
therefore space 11.1 space space straight g space of space space Pb left parenthesis NO subscript 3 right parenthesis subscript 2 space will space space give space comma
space space space fraction numerator 11.1 cross times 184 over denominator 662 end fraction equals space 3.08 space straight g space of space space NO subscript 2 space end subscript space

Answered by Varsha | 27th Nov, 2017, 12:03: PM