What is volume of O2 required at 0oC and 1 atm to burn completely 1L propane gas
What is volume of O2 required at 0oC and 1 atm to burn completely 1L propane gas
Asked by Anil
| 13th May, 2017,
12:46: PM
Expert Answer:
C3H8 + 5O2 —> 3CO2 + 4H2O
22.4L 5X 22.4L
Since 22.4 L C3H8 at STP = 5x 22.4 L of O2 at STP
Hence 1 L C3H8 at STP = 5 x 22.4/22.4 of O2 at STP
= 5 L of O2 at NTP
C3H8 + 5O2 —> 3CO2 + 4H2O
22.4L 5X 22.4L
Since 22.4 L C3H8 at STP = 5x 22.4 L of O2 at STP
Hence 1 L C3H8 at STP = 5 x 22.4/22.4 of O2 at STP
= 5 L of O2 at NTP
Answered by Vaibhav Chavan
| 13th May, 2017,
06:26: PM
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