what is the volume of tetrahedron , the sides of whose base are 9 cm,12cm and 15cm and height 20cm

Asked by ayushikas | 26th Jan, 2010, 10:16: PM

Expert Answer:

Area of a tetrahedron = 1/3 Χ area of baseΧ height

Area of base triangle with sides 9 ,12 and 15 cm is

s = (9+12+15)/2 =18

Sqrt(18 Χ 9 Χ6Χ3)=54

Volume of tetrahedron = 18Χ20=360 cm3

Answered by  | 27th Jan, 2010, 10:42: AM

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